- Question 6:A dilute ferrous sulphate solution was gradually added to the ..
- A dilute ferrous sulphate solution was gradually added to the beaker containing acidified permanganate solution. The light purple colour of the soluti
- The colour disappears due to dilution, no reaction is involved
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Question 6:A dilute ferrous sulphate solution was gradually added to the ..
Question 5: Three beakers labelled as A, B and C each containing 25 mL of water were taken. A small amount of NaOH, anhydrous CuS O 4 and NaCl were added to the beakers A, B and C respectively. It was observed that there was an increase in the temperature of the solutions contained in beakers A and B, whereas in case of beaker C, the temperature of the solution falls. Which one of the following statement(s) is(are) correct? (i) In beakers A and B, exothermic process has occurred. (ii) In beakers A and B, endothermic process has occurred. (iii) In beaker C exothermic process has occurred. (iv) In beaker C endothermic process has occurred. Answer: When a dilute ferrous sulphate solution was gradually added to the beaker containing acidified permanganate solution, acidified permanganate gets reduced to MnS O 4 and ferrous sulphate gets oxidised to F e 2 ( S O 4 ) 3 due to which the light purple colour of the solution fades and finally disappears. Hence, the correct answer is option A. Views: 5,556 (a) Mg ( s ) + C l 2 ( g ) → MgC l 2 ( s ) (b) HgO ( s ) → Heat Hg ( l ) + O 2 ( g ) (c) Na ( s ) + S ( s ) → Fuse Na 2 S ( s ) (d) TiC l 4 ( l ) + Mg ( s ) → Ti ( s ) + MgC l 2 ( s ) (e) CaO ( s ) + Si O 2 ( s ) → CaSi O 3 ( s ) (f) H 2 O 2 ( l ) → UV H 2 O ( l ) + O 2 ( g ) Question 6: A dilute ferrous sulphate solution was gradually added to the beaker containing acidified permanganate solution. The light purple colour of the solution fades and f...
A dilute ferrous sulphate solution was gradually added to the beaker containing acidified permanganate solution. The light purple colour of the soluti
A dilute ferrous sulphate solution was gradually added to the beaker containing acidified permanganate solution. The light purple colour of the solution fades and finally disappears. Which of the following is the correct explanation for the observation? A. `KMnO_(4)` is an oxidising agent and it oxidises `FeSO_(4)` B. (b) `FeSO_(4)` acts as an oxidising agent and it oxidises `KMnO_(4)` C. The colour disappears due to dilution , no reaction in involved D. `KMnO_(4)` is an unstable compound and decomposes in presence of `FeSO_(4)` to a colourless compound.
The colour disappears due to dilution, no reaction is involved
The correct Answer is a A dilute ferrous sulphate solution was gradually added to the beaker containing acidified permanganate solution. A permanganate solution is usually purple in colour. The light purple colour of the solution fades and finally disappears. This is because Potassium permanganate ( K M n O 4 ) is relatively an unstable compound, it tends to decompose in the presence of ferrous sulphate ( F e S O 4 ). This changes the colour of the solution from purple to colourless. The F e S O 4 gets oxidised to F e ( S O 4 ) as K M n O 4, acts as a good oxidising agent in an acidic medium.
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