Class 9 maths ex 8.1

RD Sharma Solutions for Class 9 Maths are given here for Chapter 8 – Lines and Angles. In order to make concepts easier for students, we have provided RD Sharma Class 9 Maths Chapter 8 solutions to help them go through several solved exercises and, at the same time, practise the questions. RD Sharma Solutions for Class 9 can help students discover new ways to solve difficult problems. They can download Previous Next Access Answers to Maths RD Sharma Solutions for Class 9 Chapter 8 Lines and Angles Exercise 8.1 Page Number 8.7 Question 1: Write the complement of each of the following angles: (i)20 0 (ii)35 0 (iii)90 0 (iv) 77 0 (v)30 0 Solution: (i) The sum of an angle and its complement = 90 0 Therefore, the complement of 20 0 = 90 0– 20 0 = 70 0 (ii) The sum of an angle and its complement = 90 0 Therefore, the complement of 35° = 90°– 35° = 55 (iii) The sum of an angle and its complement = 90 0 Therefore, the complement of 90 0 = 90 0– 90 0 = 0 0 (iv) The sum of an angle and its complement = 90 0 Therefore, the complement of 77 0 = 90°– 77 0 = 13 0 (v) The sum of an angle and its complement = 90 0 Therefore, the complement of 30 0 = 90 0– 30 0 = 60 0 Question 2 : Write the supplement of each of the following angles: (i) 54 0 (ii) 132 0 (iii) 138 0 Solution: (i) The sum of an angle and its supplement = 180 0. Therefore supplement of angle 54 0 = 180 0– 54 0 = 126 0 (ii) The sum of an angle and its supplement = 180 0. Therefore supplement of angle 132 0 = 180 0– 132 0 = 48 ...

Get here all the question answers with suitable solutions for ex. 8.1 of grade 9 mathematics updated for new academic session 2023-2024. UP Board students can also use these solutions as UP Board Solutions for their help as there are applicable in Uttar Pradesh Board. Solutions and available in Hindi Medium as well as English Medium videos format with PDF file format free to use online or download to use offline. What to Study in Class 9 Maths Chapter 8 We have studied many properties of a triangle so far in the mathematics chapters of classes 9 and 6, and we know that by adding three non-collinear points in pairs, the figure thus obtained is a triangle. We mark the four points and see what we get by matching them in couples in order. Note that if all the ends meet together (on the same line), we get only one segment; if three of the four points match, we get a triangle, and if four of them If three points do not meet each other, then we get a closed figure with four. Sides. Thus a shape formed by the union of four points in a sequence is called a quadrilateral. In Mathematics Class 9, Chapter 8, we will consider only different types of quadrilaterals. Quadrilateral in daily life A quadrilateral has four sides, four angles, and four corners. In quadrilateral ABCD, AB, BC, CD, and DA are four arms; A, B, C, and D are four corners, and A, B, C, and D are four angles. Now join the opposite corner with C and B with D and AC. AC and BD are two diagonals of the quadrilateral ABC...

Transcript Ex 8.1, 1 The angles of quadrilateral are in the ratio 3 : 5 : 9 : 13. Find all the angles of the quadrilateral. Let angles in the ratio 3: 5: 9: 13 be a, b, c & d Let a = 3x , b = 5x , c = 9x, d = 13x where x is any number We know that Sum of angles of a quadrilateral is 360° , a + b + c + d = 360° 3x + 5x + 9x + 13x = 360° 30x = 360° x = ("360" °)/"30" x = 12° Hence, the angles are a = 3x = 3 × 12° = 36° b = 5x = 5 × 12° = 60° c = 9x = 9 × 12° = 108° d = 13x = 13 × 12° = 156° Show More

NCERT Solutions Class 9 Maths Chapter 8 Quadrilaterals Exercise 8.1 are provided here. These solutions are prepared by expert teachers to guide you in your exam preparation. The solutions are always prepared by following NCERT guidelines, so that it covers the whole syllabus accordingly. Our CBSE NCERT Solutions for Class 9 Maths Chapter 8 Quadrilaterals Ex 8.1 Access NCERT Solutions for Class 9 Maths Chapter 8 Quadrilaterals – All Exercises Below we have provided the links to check solutions of the other exercises of the chapter. •