In a family the father took 1/4 of the cake

Father took 1/4 of the cake and also 3 times of others Lets say there are 'n' number of other people in the family except father Now each take 1 part of the cake ==> Father took 3 parts of the cake 3 parts of cake = 1/4 of cake ==> 1 cake = 4*3 = 12 parts Now father took 3 parts, so remaining 9 parts are take by other family members each So there are 9 other people in the family except father Including father, total = 10 • • : 0 Share the Knowledge You can help us to improve by giving your valuable suggestions at [email protected] By using the service of this site, I agree that I will serve wholeheartedly and will not indulge in any sort of activity that threats the integrity of the organisation I am working for / I work for. I have a firm believe in the notion that knowledge should be open source and helping the needy and deserving part of society will always be my motto.

Suppose amount of cake=100 Father took = 1/4 * 100 = 25 Remaining = 100 -25 = 75 Let the number of people = x Distribution to the family members = 75(remaining amount of cake) / x (number of family members) Its given father had 3 times as much as each of the other members had, Therefore, 25(Father’s amount of cake) = 3 times as much as each of the other members (75/x) then, 25= 3 * (75/x) x=9 Total= 9 +1(Father)=10 family members. •

Given: The father takes 1/4 portion of a cake = 3 times the portion taken by each of the other members Calculation: Let the number of family be n except father Let the whole cake be 100 units Father ate cake = (100× 1/4) units ⇒ 25 units Remaining cake= (100– 25) units ⇒ 75 units Distribution of cakes in n members = (75/n) units/member ⇒ 25 = 3 × (75/n) ⇒ n = 9 Numbers of members in family = (9 + 1) ⇒ 10 ∴ The total number of member of the family is 10

Given: In a family, the father took 1/4 of the cake and he had 3 times as much as each of the other members had. Calculation: Let the total number of the family member excluding father be 'x' and the amount of cake be 100 units ⇒ share of cake taken by father = 100× 1/4 = 25 units ⇒ remaining share of cake taken by family member = (100 - 25)/x also, share of cake with fatherhad 3 times as much as each of the other members had ⇒ 25 = 3× 75/x ⇒ x = 9 ∴ total number of the family members including father= 9 + 1 = 10

Father took 1/4 of the cake and also 3 times of others Lets say there are 'n' number of other people in the family except father Now each take 1 part of the cake ==> Father took 3 parts of the cake 3 parts of cake = 1/4 of cake ==> 1 cake = 4*3 = 12 parts Now father took 3 parts, so remaining 9 parts are take by other family members each So there are 9 other people in the family except father Including father, total = 10 • • : 0 Share the Knowledge You can help us to improve by giving your valuable suggestions at [email protected] By using the service of this site, I agree that I will serve wholeheartedly and will not indulge in any sort of activity that threats the integrity of the organisation I am working for / I work for. I have a firm believe in the notion that knowledge should be open source and helping the needy and deserving part of society will always be my motto.

Suppose amount of cake=100 Father took = 1/4 * 100 = 25 Remaining = 100 -25 = 75 Let the number of people = x Distribution to the family members = 75(remaining amount of cake) / x (number of family members) Its given father had 3 times as much as each of the other members had, Therefore, 25(Father’s amount of cake) = 3 times as much as each of the other members (75/x) then, 25= 3 * (75/x) x=9 Total= 9 +1(Father)=10 family members. •

Given: In a family, the father took 1/4 of the cake and he had 3 times as much as each of the other members had. Calculation: Let the total number of the family member excluding father be 'x' and the amount of cake be 100 units ⇒ share of cake taken by father = 100× 1/4 = 25 units ⇒ remaining share of cake taken by family member = (100 - 25)/x also, share of cake with fatherhad 3 times as much as each of the other members had ⇒ 25 = 3× 75/x ⇒ x = 9 ∴ total number of the family members including father= 9 + 1 = 10

Given: The father takes 1/4 portion of a cake = 3 times the portion taken by each of the other members Calculation: Let the number of family be n except father Let the whole cake be 100 units Father ate cake = (100× 1/4) units ⇒ 25 units Remaining cake= (100– 25) units ⇒ 75 units Distribution of cakes in n members = (75/n) units/member ⇒ 25 = 3 × (75/n) ⇒ n = 9 Numbers of members in family = (9 + 1) ⇒ 10 ∴ The total number of member of the family is 10