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Practice Questions,Session- 2022-23,Class- X,Subject- Mathematics (Standard),Find the smallest pair of 4-digit numbers, such that the difference between them.



Now the unit digits of the powers of 7 are Power -- Unit digit 0 -- 1 1 -- 7 2 -- 9 3 -- 3 4 -- 1 and you are back into the loop (of 1-7-9-3). So, you only need consider 7 to the power 173 modulo 4. That is, the remainder when 173 is divided by 4. 173 = 1 mod 4 So the unit digit of 3127173 is the same as the unit digit of 7173 which is the unit.



Then placing the numbers in the form $1,n,3,n-2,5,n-4.,.,n-1,2$ does the trick. And most people believe there is an infinite number of twin primes. In fact we might be able to get somewhere using one of the following classes is infinite: twin primes, sexy primes, cousin primes. $\endgroup$ –



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the LCM for this two numbers will be nothing but LCM will be nothing but is equals to 2 into 2 into 5 2 into 2 into 25 so here we will get two two Za four 4520 so the.



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The sum of all two digit positive numbers which when divided by 7 yield 2 or 5 as remainder is: The sum of all two digit positive numbers which when divided by 7.



Best answer Prime factorization: 15 = 3 × 5 24 = 23 × 3 36 = 22 × 32 LCM = product of greatest power of each prime factor involved in the numbers = 23 × 32 × 5 = 360 Now, the greatest four digit number is 9999. On dividing 9999 by 360 we get 279 as remainder. Thus, 9999 – 279 = 9720 is exactly divisible by 360.



Factors of 18, 24 and 32 are. 18 = 2 × 3 × 3 24 = 2 × 2 × 2 × 3 32 = 2 × 2 × 2 × 2 × 2. Thus the L.C.M. of 18, 24 and 32 is 2 × 2 × 2 × 2 × 2 × 3 × 3 = 288. To get the smallest four digit number that is divisible by 288, we have to write the multiples of 288. 288 × 2 = 576 288 × 3 = 864 288 × 4 = 1152. Hence 1152 is the.



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Solution Verified by Toppr Let the one's place be y and tens digit be x. then, Number = 10x + y. ∴ Given, (x) = 2y ∴5x=2y⋯(i) But, if 18 is subtracted, then, number gets reversed ie. 10y + x. ∴(10x+y)−18=10y+x ⇒10x+y−18=10y+x ⇒10x−x+y−10y−18=0 ⇒9x−9y−18=0 ⇒x−y−2=0 Putting [y= 25x] ⇒x− 25x−2=0 ⇒2x−x−2=0 ∴y= 2x y = 1 ⇒x=2 ∴ Number = 21