The vapour pressure of pure benzene at a certain temperature is 0.850 bar

  1. Solved The vapour pressure of pure benzene at a
  2. Solved Problem 3 The vapour pressure of pure benzene at a
  3. Saxample 2.6 The vapour pressure of pure benzene at a certain temperature..
  4. The vapour pressure of pure benzene at a certain temperature is 0.850 bar.
  5. The vapour pressure of pure benzene at a certain temperature is 0.850 bar. A non volatile, non electrolyte solid weighing 0.5 g when added to 39.0 g of benzene molar mass 78 gmol 1 . The vapour pressure of the solution then is 0.845 bar. What is the molar mass of the solid substance?A. 170 gmol 1B. 270 gmol 1С. 370 gmol 1D. 140 gmol 1


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Solved The vapour pressure of pure benzene at a

This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer See Answer See Answer done loading Question:The vapour pressure of pure benzene at a certain temperature is 0.850 bar. A non-volatile solid weighing 0.5 gwhen added to 39.0 g of benzene. vapour pressure of solution then is 0.845 bar. what is the molar mass of solid substance

Solved Problem 3 The vapour pressure of pure benzene at a

This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer See Answer See Answer done loading Question:Problem 3 The vapour pressure of pure benzene at a certain temperature is 0.850 bar. A non- volatile, non-electrolyte solid weighing 0.5 g is added to 39.0 g of benzene (molar mass 78 g mol-1). The vapour pressure of the solution then is 0.845 bar. What is the molar mass of the solid substance ? Problem 3 The vapour pressure of pure benzene at a certain temperature is 0.850 bar. A non- volatile, non-electrolyte solid weighing 0.5 g is added to 39.0 g of benzene (molar mass 78 g mol-1). The vapour pressure of the solution then is 0.845 bar. What is the molar mass of the solid substance ? Previous question Next question

Saxample 2.6 The vapour pressure of pure benzene at a certain temperature..

Saxample 2.6 The vapour pressure of pure benzene at a certain temperature is 0.854 bar. A non-volatile, non-electrolyte solld welghing 0.5 g when added th 39.0 g of beruene (molar mass 78 g mol − 1 ). Vapour pressure of the solutis then, is 0.845 bar. What is the molar mass of the solld stibstamces Solution The various quantities known to us are as follows: p 1 0 ​ = 0.850 bar: p = 0.845 bar: M 1 ​ = 78 g mol − 1 : w 2 ​ = 0.5 g ; w 1 ​ = 39 g Substituting these values in equation (2.28), we get. 0.850 bar 0.850 bar − 0.845 bar ​ = M 2 ​ × 39 B 0.5 g × 78 g mol − 1 ​ Therefore, M 2 ​ = 170 g mol − 1 2.6.2 Elevation of We have learnt in Unit 5. Class XI, that the vapour pressure Boiling Point liquid Increases with increase of temperature. It bolls at temperature at which its vapour pressure is equal to the atmosp? pressure, For example, water bolls at 373.15 K ( 10 0 ∘ C ) becau whe termperature the vapour pressure of water is 1.013 Views: 5,394 = i × theoritical calligatine proparty \[ \begin \] Saxample 2.6 The vapour pressure of pure benzene at a certain temperature is 0.854 bar. A non-volatile, non-electrolyte solld welghing 0.5 g when added th 39.0 g of beruene (molar mass 78 g mol − 1 ). Vapour pressure of the solutis then, is 0.845 bar. What is the molar mass of the solld stibstamces Solution The various quantities known to us are as follows: p 1 0 ​ = 0.850 bar: p = 0.845 bar: M 1 ​ = 78 g mol − 1 : w 2 ​ = 0.5 g ; w 1 ​ = 39 g Substituting these values in equation ...

The vapour pressure of pure benzene at a certain temperature is 0.850 bar.

The vapour pressure of pure benzene at a certain temperature is 0.850 bar. A non-volatile, non-electrolye solid weighing 0.5 g is added to 39.0 g of benzene (molar mass 78 g/mol). The vapour pressure of the solution then is 0.845 bar. What is the molecular mass of the solid substance? (a) 58 (b) 180 (c) 170 (d) 145

The vapour pressure of pure benzene at a certain temperature is 0.850 bar. A non volatile, non electrolyte solid weighing 0.5 g when added to 39.0 g of benzene molar mass 78 gmol 1 . The vapour pressure of the solution then is 0.845 bar. What is the molar mass of the solid substance?A. 170 gmol 1B. 270 gmol 1С. 370 gmol 1D. 140 gmol 1

The vapour pressure of pure benzene at a certain temperature is 0.850 bar. A non volatile, non electrolyte solid weighing 0.5 g when added to 39.0 g of benzene molar mass 78 gmol 1 . The vapour pressure of the solution then is 0.845 bar. What is the molar mass of the solid substance?A. 170 gmol 1B. 270 gmol 1С. 370 gmol 1D. 140 gmol 1 The correct option is A 170 g m o l − 1 The given values are P ∘ = 0.850 b a r , P s = 0.845 b a r ; M w 1 = 78 g m o l − 1 W 2 = 0.5 g ; W 1 = 39 g Now using equation P ∘ − P s P ∘ = W 1 × M w 1 M w 2 × W 1 On substituting all the given values, we get 0.850 − 0.845 0.850 = 0.5 g × 78 g m o l − 1 M w 2 × 39 g ∴ M w 2 = 170 g m o l − 1 The vapour pressure of pure Benzene at a certain temperature is 0.850 b a r. A non-volatile, non-electrolyte solid weighing 0.5 g when added to 39.0 g of benzene ( m o l a r m a s s 78 g m o l − 1 ). Vapour pressure of the solution, then is 0.845 b a r. What is the molar mass of the solid substance?

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