Two students appeared at an examination. one of them secured 9 marks more than the other and his marks were 56% of the sum of their marks. what are the marks obtained by both of them?

  1. Two students appeared for an examination. One of them secured 9 marks more than the other and his marks were 56 % of the sum of their marks. The marks
  2. Two students appeared at an examination. One of them secured 9 marks more than the other and his marks were 56% of the sum of their marks. What are the marks obtained by both of them?${\\text{A}}{\\text{. 25 and 78}} \\\\{\\text{B}}{\\text{. 58 and 77}} \\\\{\\text{C}}{\\text{. 33 and 42}} \\\\{\\text{D}}{\\text{. 56 and 63}} \\\\ $
  3. Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks ob
  4. [Solved] Two students appeared at an examination. One of them secured
  5. Infosys Percentages Questions and Answers Quiz


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Two students appeared for an examination. One of them secured 9 marks more than the other and his marks were 56 % of the sum of their marks. The marks

Correct Answer - Option 3 : 33 and 42 Formula Used Percentage = Actual/Total × 100 Calculation Let the marks obtained by first student = a Then marks obtained by second student = a + 9 According to the question, ⇒ a + 9 = ( a + a + 9 ) × 56 % ⇒ 12a = 396 ⇒ a = 33 Marks of the first student = 33 Marks of second student = 33 + 9 = 42 ∴ The Required answer is 33 and 42 Categories • • (31.9k) • (8.8k) • (764k) • (248k) • (2.9k) • (5.2k) • (664) • (121k) • (72.1k) • (3.8k) • (19.6k) • (1.4k) • (14.2k) • (12.5k) • (9.3k) • (7.7k) • (3.9k) • (6.7k) • (63.8k) • (26.6k) • (23.7k) • (14.6k) • (25.7k) • (530) • (84) • (765) • (49.1k) • (63.8k) • (1.8k) • (59.3k) • (24.5k)

Two students appeared at an examination. One of them secured 9 marks more than the other and his marks were 56% of the sum of their marks. What are the marks obtained by both of them?${\\text{A}}{\\text{. 25 and 78}} \\\\{\\text{B}}{\\text{. 58 and 77}} \\\\{\\text{C}}{\\text{. 33 and 42}} \\\\{\\text{D}}{\\text{. 56 and 63}} \\\\ $

Two students appeared at an examination. One of them secured 9 marks more than the other and his marks were 56% of the sum of their marks. What are the marks obtained by both of them?$ \\\\ $ Two students appeared at an examination. One of them secured 9 marks more than the other and his marks were 56% of the sum of their marks. What are the marks obtained by both of them? $ \\ $ Hint: In this question, we would assume one of the numbers as x and then proceed by applying the given constraints. After applying the constraints we would get a linear equation in x. This will help us simplify the question and reach the answer. Complete step-by-step answer: Let the marks of a student be x. So, the marks of another number is (x+9). We have been also given that (x+9) is 56% of the sum of their both marks. So $x + 9 = \dfrac \right)$ $ \Rightarrow 100x + 900 = 112x + 504$ $ \Rightarrow 12x = 396$ $ \Rightarrow x = 33$ So, the marks are 33 and 42 Hence, option C is correct. Note: Whenever we face such types of problems the value point to remember is that we need to have a good grasp over linear equations in one variable and number theory. In these types of questions, we should always assume one of the numbers and then applying constraints move ahead. This helps in getting us the required expressions and gets us on the right track to reach the answer.

Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks ob

Correct Answer - Option 4 : 42, 33 Given: One student score 9 marks more than the other student. The same student gets marks 56% of the sum of their marks. Calculation: Let the marks of one student be x. Let the marks of other student be (x + 9). The sum of their marks = x + x + 9 = 2x + 9 According to the question; ⇒ (x + 9) = 56/100 × (2x + 9) ⇒ (x + 9) = 14/25 × (2x + 9) ⇒ 25x + 225 = 28x + 126 ⇒ 3x = 99 ⇒ x = 33 The marks of the one student = 33 The marks of the other student = 33 + 9 = 42 ∴ The marks of the both students is 33, 42. Categories • • (31.9k) • (8.8k) • (764k) • (248k) • (10.0k) • (5.6k) • (36.3k) • (7.5k) • (1.6k) • (2.0k) • (683) • (828) • (7) • (10.7k) • (11.8k) • (11.2k) • (6.8k) • (4.9k) • (5.3k) • (2.8k) • (19.9k) • (936) • (2.9k) • (5.2k) • (664) • (121k) • (72.1k) • (3.8k) • (19.6k) • (1.4k) • (14.2k) • (12.5k) • (9.3k) • (7.7k) • (3.9k) • (6.7k) • (63.8k) • (26.6k) • (23.7k) • (14.6k) • (25.7k) • (530) • (84) • (765) • (49.1k) • (63.8k) • (1.8k) • (59.3k) • (24.5k)

[Solved] Two students appeared at an examination. One of them secured

Given: One student scored 9 marks more than the other student. The same student gets marks56% of the sum of their marks. Calculation: Let the marks of one student be x. Let the marks of other students be (x + 9). The sum of their marks = x + x + 9 = 2x + 9 According to the question; ⇒ (x + 9) = 56/100 × (2x + 9) ⇒(x + 9) = 14/25 × (2x + 9) ⇒ 25x + 225 = 28x + 126 ⇒ 3x = 99 ⇒ x = 33 The marks of the one student = 33 Themarks of the other student = 33 + 9 = 42 ∴ The marks of both students are 42, 33. CISF ASI Admit Card Released!CISF ASINew Notification Out. Candidates could apply from 26th September to 25th October 2022 for a total of 122 vacancies. The vacancies were released for ASI (Stenographer) position and candidates between the age of 18 to 25 with Class 12th certificates were eligible to apply. The candidates will have to undergo the selection process consisting of 5 stages in order Physical Standards Test, Documentation. Written Exam, Skill Test, and Medical Examination. The finally selected candidates will receive a salary between Rs.29200 to Rs 92300. Check the CISF ASI Eligibility to know the basic requirements.

Infosys Percentages Questions and Answers Quiz

It looks like question assumes Revenue= Consumption x tax amount per commodity Let, commodity = 100, tax amount per commodity = 100 Revenue = 100 × 100 = 10000 new consumption = 100(100+15)/100= 115 New tax amount per commodity= 100(100 - 20)/100= 80 New revenue = 115 × 80 = 9200 Decrease in revenue = 10000 - 9200= 800 Percentage decrease in revenue =800x100/10000= 8%