- How Much Energy is Required to Launch a Satellite of Mass m?
- What is the minimum energy required to launch a satellite of mass m from the surface of a planet of mass M and radius R in a circular orbit at an altitude of 2R?
- Solved What is the minimum energy required to launch a
- What is the minimum energy required to launch a satellite of mass m from ..
- [Solved] A satellite of mass m is in a circular orbit of Radius 2RE a
- What is the minimum energy required to launch a satellite of mass m f
How Much Energy is Required to Launch a Satellite of Mass m?
India – the minimum energy required to launch a satellite of mass m the minimum energy required to launch a satellite of mass m– We are going to start the discussion about THE MINIMUM ENERGY REQUIRED TO LAUNCH A SATELLITE OF MASS M as per our readers’ demands and comments. If you want to know about this India topic, continue reading and learn more. • • • • • • • • About the minimum energy required to launch a satellite of mass m What is the minimum energy required to launch a satellite of mass m from the surface of a planet of mass M and radius R in a circular orbit at an altitude of 2R. A 6R5GmM B 3R2GmM C 2RGmM D 3RGmM Medium Solution Verified by Toppr Corect option is A) Given that, Mass of satellite =m Mass of planet =M Radius =R Altitude h=2R Now,. People Also Read: What is The minimum energy required to launch a m kg satellite from The minimum energy required to launch amkg satellite from earth's surface in a circular orbit at an altitude of 2R where R is the radius of earth, will be: A 3mgR B 65mgR C 2mgR D 51mgR Medium Solution Verified by Toppr Corect option is B) The kinetic energy at altitude 2R is = 6RGMm The gravitational potential energy at altitude 2R is = 3R–GMm. What is the minimum energy required to launch a satellite of mass m from the surface of a planet of mass M and radius R in a circular orbit at an altitude of 2R. A 3R2GmM B 2RGmM C 3RGmM D 6R5GmM Medium Solution Verified by Toppr Corect option is D) Given that, Mass of satellite =m Mass of planet =...
What is the minimum energy required to launch a satellite of mass m from the surface of a planet of mass M and radius R in a circular orbit at an altitude of 2R?
Solution: Given that, Mass of satellite = m Mass of planet = M Radius = R Altitude h = 2 R Now, The gravitational potential energy P.E = r − G m Potential energy at altitude = 3 R G m M Orbital velocity v 0 = R + h G m M Now, the total energy is E f = 2 1 m v 0 2 − 3 R G m M E f = 2 1 3 R G m M − 3 R GM m E f = 3 R G m M [ 2 1 − 1 ] E f = 6 R − G m M Now, E i = E f Now, the minimum required energy K ⋅ E = R G mm − 6 R G m M K ⋅ E = 6 R 5 G m M Hence, the minimum required energy is 6 R 5 G m M
Solved What is the minimum energy required to launch a
This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer See Answer See Answer done loading Question:What is the minimum energy required to launch a satellite of mass m kg from the earth’s surface of radius R in a circular orbit at an altitude of 2R ?
What is the minimum energy required to launch a satellite of mass m from ..
Exp. (a) From conservation of energy, Total energy at the planet = Total energy at altitude − R GM m + ( K E ) s u r f a ce = − 3 R GM m + 2 1 m v A 2 … ( i ) In the orbital of planet, the necessary centripetal force is obtained by gravitational force. ∴ R + 2 R m v A 2 = ( R + 2 R ) 2 GM m ⇒ 2 v A = 3 R GM From Eqs. (i) and (ii), we get ( KE ) s u r f a ce = 6 5 R GMm Views: 5,572 R is made of two semi-circular parts (see figure). The two parts are held together by a ring made of a metal strip of cross-sectional area S and length L . L is slightly less than 2 π R. To fit the ring on the wheel, it is heated so that its temperature rises by Δ T and it just steps over the wheel. As it cools down to surrounding temperature, it presses the semi-circular parts together. If the coefficient of linear expansion of the metal is α and its Young's modulus is Y, the force that one part of the wheel applies on the other part is (a) 2 π S Y α Δ T (b) S Y α Δ T (c) π S Y α Δ T (d) 2 S Y α Δ T Views: 5,458 h' above earth surface (where, radius of earth = 6.4 × 1 0 3 km ) is E 1 and kinetic energy required for the satellite to be in a circular orbit at this height is E 2 . The value of h for which E 1 and E 2 are equal is (a) 3.2 × 1 0 3 km (b) 1.28 × 1 0 4 km (c) 6.4 × 1 0 3 km (d) 1.6 × 1 0 3 km Views: 6,080 g E and g M are the accelerations due to gravity on the surfaces of the earth and the moon respectively and if Millikan's oil drop experiment ...
[Solved] A satellite of mass m is in a circular orbit of Radius 2RE a
Concept: • The total mechanical energy of a satellite is the sum of its kinetic energy (always positive) and potential energy (may be negative). • At infinity, the gravitational potential energy of the satellite is zero. • As the Earth-satellite system is a bound system, the total energy of the satellite is negative. • Generally, the total energy of the planet andsatellite system is negative. This means the satellite cannot escape from the earth’s gravity. The energy of the satellite is calculated as = \(\frac\)
What is the minimum energy required to launch a satellite of mass m f
• New • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • •