A bike rider has to cover a distance of 400 km in 10 hours. if he covers half of the journey in 60 percent of the total time. what should be its speed to cover the remaining distance in the time left?

12 Thermodynamics • Introduction • 12.1 Zeroth Law of Thermodynamics: Thermal Equilibrium • 12.2 First law of Thermodynamics: Thermal Energy and Work • 12.3 Second Law of Thermodynamics: Entropy • 12.4 Applications of Thermodynamics: Heat Engines, Heat Pumps, and Refrigerators • Key Terms • Section Summary • Key Equations • 22 The Atom • Introduction • 22.1 The Structure of the Atom • 22.2 Nuclear Forces and Radioactivity • 22.3 Half Life and Radiometric Dating • 22.4 Nuclear Fission and Fusion • 22.5 Medical Applications of Radioactivity: Diagnostic Imaging and Radiation • Key Terms • Section Summary • Key Equations • Teacher Support The learning objectives in this section will help your students master the following standards: • (4) Science concepts. The student knows and applies the laws governing motion in a variety of situations. The student is expected to: • (C) analyze and describe accelerated motion in two dimensions using equations, including projectile and circular examples. Section Key Terms angle of rotation angular velocity arc length circular motion radius of curvature rotational motion spin tangential velocity Angle of Rotation What exactly do we mean by circular motion or rotation? Rotational motion is the circular motion of an object about an axis of rotation. We will discuss specifically circular motion and spin. Circular motion is when an object moves in a circular path. Examples of circular motion include a race car speeding around a circular curve, a t...

10 Fixed-Axis Rotation • Introduction • 10.1 Rotational Variables • 10.2 Rotation with Constant Angular Acceleration • 10.3 Relating Angular and Translational Quantities • 10.4 Moment of Inertia and Rotational Kinetic Energy • 10.5 Calculating Moments of Inertia • 10.6 Torque • 10.7 Newton’s Second Law for Rotation • 10.8 Work and Power for Rotational Motion • 13 Gravitation • Introduction • 13.1 Newton's Law of Universal Gravitation • 13.2 Gravitation Near Earth's Surface • 13.3 Gravitational Potential Energy and Total Energy • 13.4 Satellite Orbits and Energy • 13.5 Kepler's Laws of Planetary Motion • 13.6 Tidal Forces • 13.7 Einstein's Theory of Gravity • Learning Objectives By the end of this section, you will be able to: • Identify which equations of motion are to be used to solve for unknowns. • Use appropriate equations of motion to solve a two-body pursuit problem. You might guess that the greater the acceleration of, say, a car moving away from a stop sign, the greater the car’s displacement in a given time. But, we have not developed a specific equation that relates acceleration and displacement. In this section, we look at some convenient equations for kinematic relationships, starting from the definitions of displacement, velocity, and acceleration. We first investigate a single object in motion, called single-body motion. Then we investigate the motion of two objects, called two-body pursuit problems. Notation First, let us make some simplifications in notatio...

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Question 1: A racing car covers a certain distance at a speed of 320 km/hr in 5 hours. To cover the same distance in 5/3 hours it must travel at a speed of: Solution: Given Distance is constant. So, Speed is inversely proportional to time. Ratio of time 5 : 5/3 Ratio of time becomes 3 : 1 Then, Ratio of speed 1 : 3 1 unit -> 320 km/hr 3 unit -> 320 x 3 = 960 km/hr is required speed Question 2: A train running at a speed of 36 km/hr and 100 meter long. Find the time in which it passes a man standing near the railway line is : Solution: Speed = 36 km/hr Change in m/s So, speed = 36 * 5/18 = 10 m/s Time required = Distance/speed = 100/10 = 10 second Question 3: If an employee walks 10 km at a speed of 3 km/hr, he will be late by 20 minutes. If he walks at 4 km/hr, how early from the fixed time he will reach ? Solution: Time taken at 3 km/hr = Distance/speed = 10/3 Actual time is obtained by subtracting the late time So, Actual time = 10/3 – 1/3 = 9/3 = 3 hour Time taken at 4 km/hr = 10/4 hr Time difference = Actual time – time taken at 4 km/hr = 3 – 10/4 = 1/2 hour Hence, he will be early by 30 minutes. Question 4: The diameter of each wheel of a truck is 140 cm, If each wheel rotates 300 times per minute then the speed of the truck (in km/hr) (take pi=22/7) Solution: Circumference of the wheel= 2 * 22/7 * r = 2 * 22/7 * 140/2 = 440 cm Speed of the car = (440 * 300 * 60)/(1000 * 100 ) = 79.2 km/hr Question 5: A man drives at the rate of 18 km/hr, but stops at red light for 6 ...

The simplest way to remember what is the meaning of displacement is to just remember this phrase- "Displacement is the shortest distance between two points in space." To illustrate, imagine a body which travels 4m north and turns right at 90 degrees to the east, and travels 3m. So the shortest distance or DISPLACEMENT is actually the hypotenuse, or 5m. Best of Luck! The answer to this question is calculus. In calculus, Godfrey Wilhelm Leibniz used the notation d/dx to indicate when he was taking a derivative of an equation, as opposed to Isaac Newton who simply used a hash mark. (As it turns out, Leibniz's notation is much simpler to use in calculus when dealing with derivatives and integrals and the like.) So, the reason s is used is so that when you start doing calculus in physics, you don't make a confuse the displacement of an object with taking a derivative of an object and get a really bad answer. I hope that helped. The first answer was correct, displacement does need a quantity and direction. Displacement can be calculated by measuring the final distance away from a point, and then subtracting the initial distance. Displacement is key when determining velocity (which is also a vector). Velocity = displacement/time whereas speed is distance/time. If I walked to school, then i realized that I forgot my homework and ran back home (all of which took me 20 min. and I live 500 meters away from school), then my average velocity would be 0meters/20min. My average speed on ...