Ex 3.4 class 10

NCERT Solutions for Class 10 Maths Chapter 3 Pair of Linear Equations in Two Variables Ex 3.4 are part of • • • • • • • Board CBSE Textbook NCERT Class Class 10 Subject Maths Chapter Chapter 3 Chapter Name Pair of Linear Equations in Two Variables Exercise Ex 3.4 Number of Questions Solved 2 Category NCERT Solutions for Class 10 Maths Chapter 3 Pair of Linear Equations in Two Variables Ex 3.4 Ex 3.4 Class 10 Maths Question 1. Solve the following pairs of linear equations by the elimination method and the substitution method: Solution: (i) By Elimination Method: Fquations are x + y = 5 and 2x – 3y = 4 Multiply equation (i) by 2 and subtract equation (ii) from it, we have (ii) By Elimination method: Equations are 3x + 4y = 10 and 2x – 2y = 2 Multiplying equation (ii) by 2 and adding to equation (i), we (iii) By Elimination Method: (iv) By Elimination Method: 1st equation : Ex 3.4 Class 10 Maths Question 2. Form the pair of linear equations for the following problems and find their solutions (if they exist) by the elimination method: (i) If we add 1 to the numerator and subtract 1 from the denominator, a fraction reduces to 1. It becomes \(\frac \), if we only add 1 to the denominator. What is the fraction? (ii) Five years ago, Nuri was thrice as old as Sonu. Ten years later, Nuri will be twice as old as Sonu. How old are Nuri and Sonu? (iii) The sum of the digits of a two-digit number is 9. Also, nine times this number is twice the number obtained by reversing the order of t...

Free PDF download of RD Sharma Class 10 Solutions Chapter 3 - Pair of Linear Equations in Two Variables Exercise 3.4 solved by Expert Mathematics Teachers on Vedantu.com. All Chapter 3 - Pair of Linear Equations in Two Variables Ex 3.4 Questions with Solutions for RD Sharma to help you to revise the complete Syllabus and Score More marks. Vedantu is a platform that provides free NCERT Solution and other study materials for students. You can download NCERT Solutions for Class 10 Maths to help you to revise the complete Syllabus and score more marks in your examinations. Subjects like Science, Maths, Engish will become easy to study if you have access to NCERT Solutions Class 10 Science , Maths solutions, and solutions of other subjects that are available on Vedantu only. Class 10 is an important stepping stone in the life of all students in India as this is the first time they are introduced to a board-level examination. The marks secured in these examinations are the foundation of a student’s academic record and hence it should be prepared very seriously. RD Sharma is the standard textbook for students of Math as the book presents the topics in a very eloquent manner and has enough solved examples and exercises to make sure the students get a good grasp on the key concepts of the topic. The Chapter on pair of linear equations in two variables is especially important as this is the first time students are introduced to the concept of two variables and the technique to solve...

NCERT Solutions for Class 10 Maths Chapter 3 - Pair of Linear Equations in Two Variables Exercise 3.4 NCERT Solutions are very beneficial for students while preparing for board examinations. NCERT Solutions Class 10 Maths Chapter 3 – Pair of Linear Variables is an important topic for the board examinations and should be dealt with in complete detail. The solutions to the problems provided in the chapter are given in the NCERT Solutions Class 10 Maths Chapter 3 – Pair of Linear Equations in Two Variables Exercise 3.4. The The students should practise the exercises repeatedly to score well in the board examinations. NCERT Solutions contain detailed study material, including all the important topics. The subject experts have come up with accurate Download PDF carouselExampleControls111 Previous Next Access other exercise solutions of Class 10 Maths Chapter 3 – Pair of Linear Equations in Two Variables Access answers of Maths NCERT Class 10 Chapter 3 – Pair of Linear Equations in Two Variables Exercise 3.4 1. Solve the following pair of linear equations by the elimination method and the substitution method: (i) x + y = 5 and 2x – 3y = 4 (ii) 3x + 4y = 10 and 2x – 2y = 2 (iii) 3x – 5y – 4 = 0 and 9x = 2y + 7 (iv) x/2+ 2y/3 = -1 and x-y/3 = 3 Solutions: (i) x + y = 5 and 2x – 3y = 4 By the method of elimination. x + y = 5 ……………………………….. (i) 2x – 3y = 4 ……………………………..(ii) When the equation (i) is multiplied by 2, w...

NCERT Solutions for Class 10 Maths Chapter 3 Pair of Linear Equations in Two Variables Ex 3.4 – Free PDF Free PDF of NCERT Solutions for Class 10 Maths Chapter 3 Exercise 3.4 prepared by expert Mathematics teacher at Mathongo.com as per CBSE (NCERT) books guidelines. Download our Class 10 Maths Chapter 3 Pair of Linear Equations in Two Variables Ex 3.4 questions with solutions to help you to revise complete syllabus and score more marks in your exams. FREE PDF • • • • • •

Free PDF download of RS Aggarwal Solutions Class 10 Chapter 3 - Linear Equations in two variables (Ex 3D) Exercise 3.4 solved by Expert Mathematics Teachers on Vedantu.com. All Ex 3.4 Questions with Solutions for Class 10 Maths RS Aggarwal to help you to revise the complete Syllabus and Score More marks. Register for online coaching for IIT JEE (Mains & Advanced) and other engineering entrance exams.Vedantu is a platform that also provides freeCBSE Solutionsand other study materials for students. You can downloadMaths NCERT Solutions Class 10to help you to revise the complete Syllabus and score more marks in your examinations. Subjects like Science, Maths, English will become easy to study if you have access toClass 10 Science NCERT Solutions, Maths solutions, and solutions of other subjects that are available on Vedantu only. RD Sharma and RS Sharma are two of the most popular books that students consider for the preparation of their Mathematics for the board as well as further competitive examinations. These books are all about building your basic concepts strong and concepts clear. Only once these two have been established can students clear the exam with ease and confidence. Linear equation in two Variables is marked as Chapter 3 in the RS Aggarwal book for Class 10 students. It deals with the concept of how the geometry of lines can be used to solve different kinds of questions. Here are some features of the chapter: • This chapter Linear Equation In Two Variables is ...

Pair of Linear Equations in Two Variables Class 10 Solutions Exercise 3.4 RD Sharma Class 10 Solutions Pair Of Linear Equations In Two Variables Ex 3.4 Solve each of the following systems of equations by the method of cross multiplication. Question 1. x + 2y + 1 = 0 2x – 3y – 12 = 0 (C.B.S.E. 1992) Solution: Question 2. 3x + 2y + 25 = 0 2x + y + 10 = 0 (C.B.S.E. 1992) Solution: Question 3. 2x + y = 35 3x + 4y = 65 (C.B.S.E. 1993) Solution: Question 4. 2x – y = 6 x – y = 2 (C.B.S.E. 1994) Solution: Question 5. \(\frac =a+b\quad ,\quad x,y\quad \neq 0\) Solution: Question 26. mx – ny = m 2 + n 2 x + y = 2m (C.B.S.E. 2006C) Solution: Question 27. Solution: Question 28. Solution: Pair of Linear Equations in Two Variables Class 10 Solutions Exercise 3.4 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. 18. 19. 20. 21. 22. 23. 24. 25. 26. 27. 28. • • • • • • • • • • •

Table of Contents • • • • • • • • • • • • • • NCERT Solutions for Class 10 Maths Exercise 3.4 Class 10 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 10 Maths chapter wise NCERT solution for Maths Book for all the chapters can be downloaded from our website and myCBSEguide mobile app for free. NCERT solutions for Maths Pair of Linear Equations in Two Variables NCERT Solutions for Class 10 Maths Pair of Linear Equations in Two Variables 1. Solve the following pair of linear equations by the elimination method and the substitution method: (i) x + y = 5, 2x – 3y = 4 (ii) 3x + 4y = 10, 2x – 2y = 2 (iii) 3 x − 5 y – 4 = 0, 9 x = 2 y + 7 (iv) Ans. (i) x + y = 5 … (1) 2x – 3y = 4 … (2) Elimination method: Multiplying equation (1) by 2, we get equation (3) 2 x + 2 y = 10 … (3) 2 x − 3 y = 4 … (2) Subtracting equation (2) from (3), we get 5 y = 6⇒ y = Putting value of y in (1), we get x + = 5 ⇒ x = 5 − = Therefore, x = and y = Substitution method: x + y = 5 … (1) 2 x − 3 y = 4 … (2) From equation (1), we get, x = 5 − y Putting this in equation (2), we get 2 (5 − y) − 3 y = 4 ⇒ 10 − 2 y − 3 y = 4 ⇒ 5 y = 6 ⇒ y = Putting value of y in (1), we get x = 5 − = Therefore, x = and y = (ii) 3x + 4y = 10… (1) 2x – 2y = 2… (2) Elimination method: Multiplying equation (2) by 2, we...